src/tree.c

changeset 830
c4dae6fe6d5b
parent 826
21840975d541
child 833
5c926801f052
equal deleted inserted replaced
829:7d4e31d295af 830:c4dae6fe6d5b
167 // free the working queue and return 167 // free the working queue and return
168 #undef workq_add 168 #undef workq_add
169 free(work); 169 free(work);
170 return ret; 170 return ret;
171 } 171 }
172
173 static bool cx_tree_iter_valid(void const *it) {
174 struct cx_tree_iterator_s const *iter = it;
175 return iter->node != NULL;
176 }
177
178 static void *cx_tree_iter_current(void const *it) {
179 struct cx_tree_iterator_s const *iter = it;
180 return iter->node;
181 }
182
183 static void cx_tree_iter_stack_add(
184 struct cx_tree_iterator_s *iter,
185 void *node
186 ) {
187 cx_array_add(&iter->stack, &iter->depth, &iter->stack_capacity,
188 sizeof(void*), &node, cx_array_default_reallocator);
189 }
190
191 static void cx_tree_iter_next(void *it) {
192 struct cx_tree_iterator_s *iter = it;
193 // TODO: support mutating iterator
194
195 // TODO: implement
196 }
197
198
199 CxTreeIterator cx_tree_iterator(
200 void *root,
201 int passes,
202 ptrdiff_t loc_children,
203 ptrdiff_t loc_next
204 ) {
205 CxTreeIterator iter;
206 iter.loc_children = loc_children;
207 iter.loc_next = loc_next;
208 iter.requested_passes = passes;
209
210 // invalidate iterator immediately when passes is invalid
211 if ((passes & (CX_TREE_ITERATOR_ENTER |
212 CX_TREE_ITERATOR_NEXT_CHILD |
213 CX_TREE_ITERATOR_EXIT)) == 0) {
214 iter.stack = NULL;
215 iter.node = NULL;
216 return iter;
217 }
218
219 // allocate stack
220 iter.stack_capacity = 16;
221 iter.stack = malloc(sizeof(void *) * 16);
222 iter.depth = 0;
223
224 // determine start
225 if ((passes & CX_TREE_ITERATOR_ENTER) == 0) {
226 // we have to skip the first "entering" passes
227 void *s = NULL;
228 void *n = root;
229 iter.counter = 0;
230 do {
231 iter.counter++;
232 iter.source = s;
233 iter.node = n;
234 cx_tree_iter_stack_add(&iter, n);
235 s = n;
236 n = tree_children(n);
237 } while (n != NULL);
238 // found a leaf node s (might be root itself if it has no children)
239
240 // check if there is a sibling
241 n = tree_next(s);
242
243 if (n == NULL) {
244 // no sibling found, exit back to parent node
245 // TODO: implement
246 } else {
247 // there is a sibling
248 if ((passes & CX_TREE_ITERATOR_EXIT) == 0) {
249 // no exit requested, conclude that only next_child is requested
250 iter.source = s;
251 iter.node = n;
252 iter.counter++;
253 iter.current_pass = CX_TREE_ITERATOR_NEXT_CHILD;
254 } else {
255 // exit requested, so we have found our first pass
256 // iter.node and iter.source are still correct
257 iter.current_pass = CX_TREE_ITERATOR_EXIT;
258 }
259 }
260 } else {
261 // enter passes are requested, we can start by entering the root node
262 iter.source = NULL;
263 iter.node = root;
264 iter.current_pass = CX_TREE_ITERATOR_ENTER;
265 iter.counter = 1;
266 iter.depth = 1;
267 iter.stack[0] = root;
268 }
269
270 // assign base iterator functions
271 iter.base.mutating = false;
272 iter.base.remove = false;
273 iter.base.current_impl = NULL;
274 iter.base.valid = cx_tree_iter_valid;
275 iter.base.next = cx_tree_iter_next;
276 iter.base.current = cx_tree_iter_current;
277
278 return iter;
279 }

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